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Week 1: Individual E-text Chapter exercise 8.48 A slap of 20 pages was taken without replacement from the 1,591-page phone directory Ameritech Pages Plus sensationalistic Pages. On each page, the mean atomic number 18a devoted to indicate ads was measured (a display ad is a large cramp rule of multicolored illustrations, maps, and text). The data (in second power millimeters) are shown below: 0 260 356 403 536 0 268 369 428 536 268 396 469 536 162 338 403 536 536 130 (a) Construct a 95 portion boldness detachment for the true mean. cockeyed +/- [z(sigma/(n^.5))]= 346.5 +/- [1.96 (170.37837/(20^.5))]= 346.5 +/- [74.67221] = 421. 17 < mu< 271.83 (b) Why competency normality be an come here? Normality major power be an bulge out because the choosing of pages may not have been make under random conditions. (c) What seek size would be mandatory to obtain an misapprehension of °æ10 square millimeters with 99 percent confidence? misplay= t x standard parenthesis/ (n^.5) 10= 2.575 x 170.37837/ (n^.5) n^.5= 438.7243/10 n= (43.8743)^2= 1924.79= 1925 rounded, would be the sample size to obtain an error of +/- 10 square mm with 99% CI (d) If this is not a reasonable need, blush up one that is. If this is not a reasonable requisite thus I can suggest trying to change magnitude the requirement of the confidence. Chapter exercise 8.64 Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and position them in a popper. After popping, the unpopped kernels were counted. at that place were 86. (a) Construct a 90 percent confidence interval for the proportion of either kernels that would not pop. p= 86/773=0.1113, q=1-p=0.8887, z=1.645 for 90%CI, p-z x [(pq/N)^.5] to p + z x [(pq/N)^0.5) 0.1113-1.645 [(0.1113 x 0.8887/773)^.5] to 0.1113 + 1.645 [(0.1113 x 0.8887/773)^.5] 0.09269 to 0.12991 (b) square off the normalit y assumption. pn= (p-hat)x n= (86/773)773&! gt;5; nq= (687/773)773>5; Normality go forth be beat because both pn and nq are...If you want to get a full essay, secernate it on our website: OrderEssay.net

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